A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is $33$ and the height of the cylinder is $17$ . If the volume of the solid is $84 pi$ , what is the area of the base of the cylinder?

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Answer 1 · 2017-02-16T07:45:18

The area is $=3pi=9.42u^2$

Let $a=$ area of the base

Volume of cone is $V_(co)=1/3*a*h_(co)$

Volume of cylinder is $V_(cy)=a*h_(cy)$

Total volume

$V=V_(co)+V_(cy)$

$V=1/3ah_(co)+ah_(cy)$

$84pi=a(1/3*33+17)$

$84pi=a*28$

$a=84/28pi=3pi$

$a=9.42$

A solid consists of a cone on top of a cylinder with a radius equal to that of the cone. The height of the cone is 33 33 and the height of the cylinder is 17 17 . If the volume of the solid is 84 pi84 pi, what is the area of the base of the cylinder?