A solid disk, spinning counter-clockwise, has a mass of #1 kg# and a radius of #3 m#. If a point on the edge of the disk is moving at #9 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer

Answer:

Angular Momentum #L=13.5" "kg*m^2/("second")#
Angular Velocity #omega=3" "(rad)/sec#

Explanation:

Angular Momentum #L=I*omega#

where #I=1/2*mr^2" "#Moment of inertia

#I=1/2*(1)(3^2)=4.5" "kg*m^2#

Angular Velocity

#omega=v/r#

#omega=9/3=3" "(radian)/("second")#

Angular Momentum
#L=I*omega#

#L=4.5*3=13.5" "Kg*m^2/sec#

God bless....I hope the explanation is useful.