A solid disk, spinning counter-clockwise, has a mass of #1 kg# and a radius of #5 m#. If a point on the edge of the disk is moving at #6 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

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Answer 1 · 2017-03-01T06:45:32

The angular momentum is #=94.2kgm^2s^-1#
The angular velocity is #=7.54rads^-1#

The angular velocity is

#omega=v/r#

where,

#v=6ms^(-1)#

#r=5m#

So,

#omega=(6/5)*2pi=7.54rads^-1#

The angular momentum is #L=Iomega#

For a solid disc, #I=(mr^2)/2#

So, #I=1*(5)^2/2=25/2kgm^2#

#L=7.54*25/2=94.2kgm^2s^-1#