Question

A solid disk, spinning counter-clockwise, has a mass of `18 kg` and a radius of `9/4 m`. If a point on the edge of the disk is moving at `7/3 m/s` in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

Answer 1

The angular momentum is `=47.25kgm^2s^-1`
The angular velocity is `=1.037rads^-1`

Explanation:

The angular velocity is

`omega=(Deltatheta)/(Deltat)`

`v=r*((Deltatheta)/(Deltat))=r omega`

`omega=v/r`

where,

`v=7/3ms^(-1)`

`r=9/4m`

So,

`omega=(7/3)/(9/4)=28/27=1.037rads^-1`

The angular momentum is `L=Iomega`

where `I` is the moment of inertia

For a solid disc, `I=(mr^2)/2`

So, `I=18*(9/4)^2/2=729/16kgm^2`

`L=729/16*1.037=47.25kgm^2s^-1`