A solid disk, spinning counter-clockwise, has a mass of #4 kg# and a radius of #3/7 m#. If a point on the edge of the disk is moving at #5/9 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer
Jun 15, 2016

Answer:

#L = Iw = MR^2*v/R = (4)(3/7)^2*(5/9)/(3/7) = 0.950#

Explanation:

Like linear momentum;
p = mv.

Angular momentum equals the angular component of mass multiplied by the angular velocity,
hence;
L (angular momentum) = I (inertia) x w (angular velocity).

Inertia of a solid disk = #MR^2#, where R = radius, and M = mass of disk.

Angular velocity equals tangential velocity divided by radius.