A solid disk, spinning counter-clockwise, has a mass of #6 kg# and a radius of #3/5 m#. If a point on the edge of the disk is moving at #1 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer
Feb 2, 2017

Answer:

The angular momentum is #=11.3kgms^-1#
The angular velocity is #=10.5rads^-1#

Explanation:

The angular velocity is

#omega=v/r#

where,

#v=1ms^(-1)#

#r=3/5m#

So,

#omega=1/(3/5)*2pi=10/3pi =10.5rads^-1#

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

For a solid disc, #I=(mr^2)/2#

So, #I=6*(3/5)^2/2=27/25kgm^2#

#L=10.5*27/25=11.3kgms^(-1)#