A solid disk, spinning counter-clockwise, has a mass of #6 kg# and a radius of #3 m#. If a point on the edge of the disk is moving at #1/2 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer
Feb 22, 2017

Answer:

The angular momentum is #=28.3kgm^2s^-1#
The angular velocity #=1.047rads^-1#

Explanation:

The angular velocity is

#omega=v/r#

where,

#v=1/2ms^(-1)#

#r=3m#

So,

#omega=(1/2)/3*2pi=pi/3=1.047rads^-1#

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

For a solid disc, #I=(mr^2)/2#

So, #I=6*(3)^2/2=27kgm^2#

#L=1.047*27=28.3kgm^2s^-1#