A solid disk, spinning counter-clockwise, has a mass of #8 kg# and a radius of #5/2 m#. If a point on the edge of the disk is moving at #13/4 m/s# in the direction perpendicular to the disk's radius, what is the disk's angular momentum and velocity?

1 Answer
Jan 29, 2017

Answer:

The angular momentum is #=204.2 kgms^-1#
The angular velocity is #=8.17rads^-1#

Explanation:

The angular velocity is

#omega=v/r#

where,

#v=13/4ms^(-1)#

#r=5/2m#

So,

#omega=(13/4)/(5/2)*2pi=13/5pi rad s^-1#

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

For a solid disc, #I=(mr^2)/2#

So, #I=8*(5/2)^2/2= 25kgm^2#

#L=13/5pi*25=204.2kgms^(-1)#