# A stone was dropped off a cliff and hit the ground with a speed of 104 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)?

Oct 21, 2016

$169 f t$

#### Explanation:

Applicable Kinematic equation is
${v}^{2} - {u}^{2} = 2 g h$
where $v , u , g \mathmr{and} h$ are final velocity, initial velocity, acceleration due to gravity and height of the cliff respectively.

Inserting given values we get
${104}^{2} - {0}^{2} = 2 \times 32 h$
Solving for height $h$
$h = {104}^{2} / 64$
$= 169 f t$