Question

A stone was dropped off a cliff and hit the ground with a speed of 104 ft/s. What is the height of the cliff? (Use 32 ft/s2 for the acceleration due to gravity.)?

Answer 1

`169ft`

Explanation:

Applicable Kinematic equation is
`v^2-u^2=2gh`
where `v, u, g and h` are final velocity, initial velocity, acceleration due to gravity and height of the cliff respectively.

Inserting given values we get
`104^2-0^2=2xx32h`
Solving for height `h`
`h=104^2/64`
`=169ft`