Question

A syringe contains 2.60 mL of gas at 20.0°C. What is the volume of gas after the temperature is increased to 68.0°C?

Answer 1

`V_2~=3*mL`

Explanation:

From old `"Charles' Law"` we know that `VpropT`, or `V=kT` for a given amount of gas at constant pressure. If we solve for `k`, then `V_1/T_1=V_2/T_2`, and `V_2=V_1/T_1xxT_2`.

Of course, we must use `"absolute temperatures"`, `T_1=(20.0+273.15)*K`, and `T_2=(68.0+273.15)*K`. And thus.......

`V_2=(2.60*mL)/((20.0+273.15)*K)xx(68.0+273.15)*K=3.03*mL`