A triangle has corners at points A, B, and C. Side AB has a length of #12 #. The distance between the intersection of point A's angle bisector with side BC and point B is #7 #. If side AC has a length of #21 #, what is the length of side BC?

1 Answer
May 25, 2016

BC=19.25

Explanation:

Here is a sketch (not to scale)

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To calculate the length of BC ,we require to find the length of DC.

This can be done by using the #color(blue)" Angle bisector theorem"#

For triangle ABC this is.

#color(red)(|bar(ul(color(white)(a/a)color(black)((BD)/(DC)=(AB)/(AC))color(white)(a/a)|)))#

Substitute the appropriate values into the ratio.

#rArr7/(DC)=12/21#

now cross-multiply

#rArrDCxx12=7xx21rArrDC=(7xx21)/12=12.25#

Thus BC = BD + DC = 7 + 12.25 = 19.25