# A triangle has sides A, B, and C. Sides A and B are of lengths 14 and 3, respectively, and the angle between A and B is (5pi)/12 . What is the length of side C?

c^2=a^2+b^2-2abcos(A,B)=> c^2=14^2+3^2-2*14*3*cos(5*pi/12)=> c^2=183.3=> c=13.54