A triangle has sides A, B, and C. Sides A and B are of lengths #5# and #8#, respectively, and the angle between A and B is #(11pi)/12 #. What is the length of side C?

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Mar 25, 2018

Answer:

#color(indigo)("Length of side c " = sqrt(a^2 + b^2 - (2 a b cos C)) ~~ 12.89#

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#Given : a = 5, b = 8, hat C = (11pi)/12, "To find side c"#.

Applying cosine law,

#c = sqrt(a^2 + b^2 - (2 a b cos C))#

#c = sqrt(5^2 n+ 8^2 - (2 * 5 * 8 * cos ((11pi)/12)#

#color(indigo)("Length of side c " = sqrt(25 + 64 - 80 cos ((11pi)/12)) ~~ 12.89#

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