# A triangle labeled the usual way has sides a=8, b=4 and angle C=pi/6. Find c ?

May 11, 2018

${c}^{2} = {a}^{2} + {b}^{2} - 2 a b \cos C$
 c= \sqrt{8^2+4^2-2(8)(4)(sqrt{3}/2) } = sqrt(80 - 32 sqrt(3))