A truck pulls boxes up an incline plane. The truck can exert a maximum force of $3,500 N$ . If the plane's incline is $(5 pi )/8$ and the coefficient of friction is $7/6$ , what is the maximum mass that can be pulled up at one time?

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Answer 1 · 2018-01-25T06:45:40

The mass is $=748.1kg$

http://spmphysics.onlinetuition.com.my/2013/06/inclined-plane.html

Resolving in the direction parallel to the plane $↗^+$

Let the force exerted by the truck be $F=3500N$

Let the frictional force be $=F_rN$

The coefficient of friction $mu=F_r/N=7/6$

The normal force is $N=mgcostheta$

The angle of the plane is $theta=5/8pi$

The acceleration due to gravity is $g=9.8ms^-2$
Therefore,

$F=F_r+mgsintheta$

$=muN+mgsintheta$

$=mumgcostheta+mgsintheta$

$m=F/(g(mucostheta+sintheta))$

$=3500/(9.8(7/6*cos(5/8pi)+sin(5/8pi))$

$=748.1kg$

A truck pulls boxes up an incline plane. The truck can exert a maximum force of 3,500 N3,500 N. If the plane's incline is (5 pi )/8 (5 pi )/8 and the coefficient of friction is 7/6 7/6 , what is the maximum mass that can be pulled up at one time?