A truck pulls boxes up an incline plane. The truck can exert a maximum force of #4,500 N#. If the plane's incline is #pi/8 # and the coefficient of friction is #6/5 #, what is the maximum mass that can be pulled up at one time?

1 Answer
May 20, 2016

Answer:

#m<=309.11 kg#

Explanation:

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#T>=m*g*sin alpha +u_k*m*g*cos alpha#

#4500=m*g*sin(pi/8)+6/5*m*g*cos(pi/8)#

#sin(pi/8)=0.38#

#cos(pi/8)=0.92#

#4500=m*g(0.38+6/5*0.92)#

#4500=m*g(0.38+1.104)#

#4500=m*g*1.484#

#g=9.81 N/(kg)#

#4500=9.81*m*1.484#

#4500=14.55804*m#

#m=4500/(14.55804)#

#m<=309.11 kg#