A truck pulls boxes up an incline plane. The truck can exert a maximum force of #5,600 N#. If the plane's incline is #(2 pi )/3 # and the coefficient of friction is #7/6 #, what is the maximum mass that can be pulled up at one time?
Note, by definition, an inclined plane cannot have an inclination more than
So, as we can easily observe in the picture, the forces that oppose will be (m is expressed in
#mgsintheta = 9.8xxsqrt3/2 m=8.49mN #
frictional force, opposite to the direction of tendency of movement:
# mumgcostheta = 7/6xx9.8xx1/2 mN = 5.72m N#
Hence total is:
So, for the truck the to be able to pull it up, the maximum force it can exert must be more than this: