# A very large boulder with a volume of 1200 L has a mass of 1.4 * 10^9 3g. What is the density of the boulder?

$\frac{1.4 \times {10}^{9} \cdot g}{1200 \cdot L}$ $=$ ??# $g \cdot {L}^{-} 1$. Note that by setting up the equation this way, and using actual units of mass and volume, I get a final unit that makes sense dimensionally.