A wave is described by y = (2.05 cm) sin(kx - t), where k = 2.13 rad/m, = 3.58 rad/s, x is in meters, and t is in seconds, how do you determine the amplitude, wavelength, frequency, and speed of the wave?

Jun 25, 2015

I think there is something missing...
Try this:

Explanation:

I may be wrong but I think there is a bit missing from your wave:
$y = \left(2.05 c m\right) \sin \left(k x - \textcolor{red}{\omega} t\right)$
Where $\omega = 3.58 \frac{r a d}{s}$

The amplitude is the number in front of $\sin$ so: $A = 2.05 c m = 0.0205 m$
You get the wavelength $\lambda$ from $k$ as: $k = \frac{2 \pi}{\lambda}$ so $\lambda = 2.95 m$;
Frequency is found from $\omega = \frac{2 \pi}{T} = 2 \pi \nu$ where $T$ is the period and $\nu$ is the frequency; so $\nu = 0.57 {s}^{- 1} = 0.57 H z$;
Finally, speed will be $v =$distance/time$= \frac{\lambda}{T} = l a m \mathrm{da} \nu = 1.7 \frac{m}{s}$