Question

A weather balloon is inflated to a volume of `2.2 x 10^3` L with 37.4 g of He. What is the density of He in g/L?

Answer 1

`rho="Mass"/"Volume"`

Explanation:

Here, `rho=(37.4*g)/(2.2xx10^3*L)` `=` `??g*L^-1`.

Doing the calculation like this gives an answer in `g*L^-1` as required for a density.