# According to the VSEPR theory, what is the molecular shape of H_2O?

Around oxygen there are 2 lone pairs, and 2 $O - H$ bonding pairs, arranged in a tetrahedron. But we describe molecular geometry on the basis of disposition of atoms not electron pairs. Water is a bent molecule with the $\angle H - O - H$ bent down from 109.5""^@, because of the influence of the oxygen lone pairs; $\angle H - O - H$ approx 104-105""^@.