# Alex and Veronica were discussing the definite integral #int_0^3 (x^2 − 1)dx#. Alex said it represented the total area bounded by #f(x) = x^2 - 1# and the #x#-axis , between #x = 0# and #x = 3#. Veronica said the total area was larger?

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Who was right and why? Also, calculate the area.

Who was right and why? Also, calculate the area.

##### 1 Answer

Aug 22, 2017

#### Answer:

Veronica is correct.

#### Explanation:

We have:

# f(x) = x^2-1#

And

# I = int_0^3 \ f(x) \ dx #

If we look at the graph of the function we have:

graph{x^2-1 [-10, 10, -4, 10]}

For the roots of

# x^2-1=0=> x=+-1 #

And, as we can see, for **below** the **above** .

When we evaluate the Integral, I, we get the **net area** . where the area above is counted as positive, and the area below is counted as negative.

Hence, the actual area is as follows:

# A = -int_0^1 f(x) dx + int_1^3 f(x) dx #

Which will of course be larger than the net area.

Hence, Veronica is correct.