An experiment produced 0.10 g #CO_2#, with a volume of 0.056 L at STP. If the accepted density of #CO_2# at STP is 1.96 g/L, what is the approximate percent error?

1 Answer
May 15, 2017

Answer:

The percent error is #8.2%#.

Explanation:

You have to compare the density of #"CO"_2# produced experimentally at STP to the accepted density of #"CO"_2# at STP.

#"density"="mass"/"volume"#

You are given the mass and volume of the experimentally produced #"CO"_2:##"mass"="0.10 g";##"volume"="0.056 L"#

Insert your data into the density formula and solve.

#"density CO"_2"="(0.10"g CO"_2)/(0.056"L CO"_2)="1.8 g/L"#

#"Percent error"=abs(("experimental value"-"accepted value")/("accepted value"))xx100#

Insert your data into the percent error equation.

#"Percent error"=abs(("1.8 g/L"-"1.96 g/L")/("1.96 g/L"))xx100="8.2%# (rounded to two significant figures)