# An experiment produced 0.10 g CO_2, with a volume of 0.056 L at STP. If the accepted density of CO_2 at STP is 1.96 g/L, what is the approximate percent error?

May 15, 2017

The percent error is 8.2%.

#### Explanation:

You have to compare the density of ${\text{CO}}_{2}$ produced experimentally at STP to the accepted density of ${\text{CO}}_{2}$ at STP.

$\text{density"="mass"/"volume}$

You are given the mass and volume of the experimentally produced ${\text{CO}}_{2} :$"mass"="0.10 g";$\text{volume"="0.056 L}$

Insert your data into the density formula and solve.

$\text{density CO"_2"="(0.10"g CO"_2)/(0.056"L CO"_2)="1.8 g/L}$

"Percent error"=abs(("experimental value"-"accepted value")/("accepted value"))xx100

Insert your data into the percent error equation.

"Percent error"=abs(("1.8 g/L"-"1.96 g/L")/("1.96 g/L"))xx100="8.2% (rounded to two significant figures)