# An object is thrown vertically from a height of 6 m at  3 m/s. How long will it take for the object to hit the ground?

Mar 19, 2018

Use, $s = u t - \frac{1}{2} g {t}^{2}$ to solve it.

Total displacement in reaching ground will be $- 6 m$

So,if it takes time $t$ then,

-6=3t - 1/2×9.8×t^2

$9.8 {t}^{2} - 6 t - 12 = 0$

So,$t = 1.44 s$