Question

An object is thrown vertically from a height of `6 m` at `3 m/s`. How long will it take for the object to hit the ground?

Answer 1

Use, `s=ut -1/2 g t^2` to solve it.

Total displacement in reaching ground will be `-6m`

So,if it takes time `t` then,

`-6=3t - 1/2×9.8×t^2`

`9.8t^2-6t-12=0`

So,`t=1.44s`