An object with a mass of #1 kg# is pushed along a linear path with a kinetic friction coefficient of #u_k(x)= 3x^2-2x+12 #. How much work would it take to move the object over #x in [1, 3], where x is in meters?

1 Answer
Feb 13, 2016

Answer:

#W=412,02J#

Explanation:

#W=int_1^3 mg*(3x^2-2x+12)*d x#
#W=mg int_1^3(3x^2-2x+12)*d x#
#W=mg[3*x^3/3-2*x^2/2+12x]_1^3#
#W=mg[[27-9+36]-[1-1+12]]#
#W=mg[42]#
#W=1*9,81*42#
#W=412,02J#