# An object with a mass of 12 kg is on a surface with a kinetic friction coefficient of  2 . How much force is necessary to accelerate the object horizontally at  17 m/s^2?

Apr 8, 2017

439.2 $N$

#### Explanation:

M=12 Kg
k=2 units
a =17 $m {s}^{- 2}$

${F}_{K f} = 2 \cdot 12 \cdot 9.8 N$
$\implies$235.2 N

But we know ,

${F}_{N e t} = {F}_{a p p l i e d} - {F}_{K f}$

$M \cdot {A}_{N e t} + {F}_{K f} = {F}_{A p p l i e d}$
$\implies$439.2 N