Question

An object with a mass of `12 kg` is on a surface with a kinetic friction coefficient of `2`. How much force is necessary to accelerate the object horizontally at `17 m/s^2`?

Answer 1

439.2 `N`

Explanation:

M=12 Kg
k=2 units
a =17 `ms^(-2)`

`F_(Kf)=2*12*9.8 N`
`=>`235.2 N

But we know ,

`F_(Net)=F_(applied)-F_(Kf)`

`M*A_(Net)+F_(Kf)=F_(Applied)`
`=>`439.2 N