# An object with a mass of 12 kg is revolving around a point at a distance of 12 m. If the object is making revolutions at a frequency of 1 Hz, what is the centripetal force acting on the object?

Jan 15, 2016

${F}_{c} = 576 {\pi}^{2} N$
$\approx 5684.89 N$

#### Explanation:

For Circular Motion, Centripetal Force ${F}_{c} = - m r {\omega}^{2}$

Where $m$ is the mass of the body in circular motion.

$r$ is the radius of the circle and $\omega$ is angular velocity.
$-$ sign means that the force is opposite to the radius vector and is directed towards the center.
Now $\omega = \frac{2 \pi}{T} = 2 \pi f$
Therefore, magnitude of the force $| {F}_{c} | = 4 {\pi}^{2} {f}^{2} m r$
Assuming it to be a point mass object and substituting the given values,
$| {F}_{c} | = 4 {\pi}^{2.} {1}^{2} .12 \times 12 N$