An object with a mass of #12 kg# is revolving around a point at a distance of #12 m#. If the object is making revolutions at a frequency of #1 Hz#, what is the centripetal force acting on the object?

1 Answer
Jan 15, 2016

Answer:

#F_c =576pi^2 N#
#approx 5684.89 N#

Explanation:

For Circular Motion, Centripetal Force #F_c= - mr omega^2#

Where #m# is the mass of the body in circular motion.

#r# is the radius of the circle and #omega# is angular velocity.
#-# sign means that the force is opposite to the radius vector and is directed towards the center.
Now #omega=(2pi) /T=2pif#
Therefore, magnitude of the force #|F_c|=4pi^2 f^2mr#
Assuming it to be a point mass object and substituting the given values,
#|F_c|=4pi^2. 1^2 .12 times 12 N#