Question

An object with a mass of `12 kg` is revolving around a point at a distance of `12 m`. If the object is making revolutions at a frequency of `1 Hz`, what is the centripetal force acting on the object?

Answer 1

`F_c =576pi^2 N`
`approx 5684.89 N`

Explanation:

For Circular Motion, Centripetal Force `F_c= - mr omega^2`

Where `m` is the mass of the body in circular motion.

`r` is the radius of the circle and `omega` is angular velocity.
`-` sign means that the force is opposite to the radius vector and is directed towards the center.
Now `omega=(2pi) /T=2pif`
Therefore, magnitude of the force `|F_c|=4pi^2 f^2mr`
Assuming it to be a point mass object and substituting the given values,
`|F_c|=4pi^2. 1^2 .12 times 12 N`