An object with a mass of  14 kg is lying still on a surface and is compressing a horizontal spring by 70 c m. If the spring's constant is  2 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?

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Feb 19, 2018

The coefficient of static friction is $= 0.01$

Explanation:

The mass is $m = 14 k g$

The compression of the spring is $x = 0.7 m$

The spring constant is $k = 2 k g {s}^{-} 2$

The reaction of the spring is $R = k x = 2 \cdot 0.7 = 1.4 N$

The acceleration due to gravity is $g = 9.8 m {s}^{-} 2$

The normal reaction of the object is

$N = m g = 14 \cdot 9.8 = 137.2 N$

The coefficient of static friction is

${\mu}_{s} = \frac{R}{N} = \frac{1.4}{137.2} = 0.01$

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