An object with a mass of # 14 kg# is lying still on a surface and is compressing a horizontal spring by #1 m#. If the spring's constant is # 2 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Jun 21, 2017

Answer:

The coefficint of static friction is #=0.015#

Explanation:

The coefficient of static friction is

#mu_s=F_r/N#

#F_r=k*x#

The spring constant is #k=2kgs^-2#

The compression is #x=1m#

Therefore,

#F_r=2*1=2N#

The normal force is

#N=mg=14gN#

The coefficient of static friction is

#mu_s=(2)/(14g)=0.015#