An object with a mass of # 15 kg# is lying on a surface and is compressing a horizontal spring by #2 m#. If the spring's constant is # 8 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
May 26, 2017

Answer:

The coefficient of static friction is #=0.11#

Explanation:

The coefficient of static friction is

#mu_s=F_r/N#

#F_r=k*x#

The spring constant is #k=8kgs^-2#

The compression is #x=2m#

Therefore,

#F_r=8*2=16N#

The normal force is

#N=mg=15gN#

The coefficient of static friction is

#F_r=(16)/(15g)=0.11#