An object with a mass of #15 kg# is lying still on a surface and is compressing a horizontal spring by #5/6 m#. If the spring's constant is #24 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Feb 13, 2016

Answer:

coefficient of static friction 0.1361

Explanation:

The horizontal force exerted on the object = force con.x compression = #24*5/6#=20 N
Now #mumg=# the force applied
coefficient of static friction,#mu=# #20/(mg)#= #20/(15*9.8)# = 0.1361