# An object with a mass of 150 g is dropped into 500 mL of water at 0^@C. If the object cools by 60 ^@C and the water warms by 9 ^@C, what is the specific heat of the material that the object is made of?

Sep 14, 2016

$2095 J / k g . K$

#### Explanation:

Conservation of energy : Energy lost by object equals energy gained by water.

$\therefore {\left(m c \Delta T\right)}_{o b j e c t} = {\left(m c \Delta T\right)}_{w a t e r}$

$\therefore \left(0.150\right) \left(c\right) \left(60\right) = \left(0.500\right) \left(4190\right) \left(9\right)$

$\therefore {c}_{o b j e c t} = 2095 J / k g . K$