An object with a mass of #150 g# is dropped into #500 mL# of water at #0^@C#. If the object cools by #60 ^@C# and the water warms by #9 ^@C#, what is the specific heat of the material that the object is made of?

1 Answer
Trevor Ryan.
Sep 14, 2016

#2095J//kg.K#

Explanation:

Conservation of energy : Energy lost by object equals energy gained by water.

#therefore (mc Delta T)_ (object) = (mcDeltaT)_(water)#

#therefore (0.150)(c)(60)=(0.500)(4190)(9)#

#therefore c_(object) = 2095J//kg.K#

Related questions
See all questions in Specific Heat
Impact of this question
1421 views around the world
You can reuse this answer
Creative Commons License