An object with a mass of #16 kg# is lying still on a surface and is compressing a horizontal spring by #7/8 m#. If the spring's constant is #15 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2017-05-19T08:28:09

The coeficient of friction is #=0.084#

The coefficient of static friction is

#mu_s=F_r/N#

#F_r=k*x#

The spring constant is #k=15kgs^-2#

The compression is #x=7/8m#

Therefore,

#F_r=15*7/8=105/8N#

The normal force is

#N=mg=16gN#

The coefficient of static friction is

#F_r=(105/8)/(16g)=13.125/(16g)=0.084#