An object with a mass of # 18 kg# is lying on a surface and is compressing a horizontal spring by #60 cm#. If the spring's constant is # 18 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
May 19, 2017

Answer:

The coefficient of static friction is #=0.061#

Explanation:

The coefficient of static friction is

#mu_s=F_r/N#

#F_r=k*x#

The spring constant is #k=18kgs^-2#

The compression is #x=0.6m#

Therefore,

#F_r=18*0.6=10.8N#

The normal force is

#N=mg=18gN#

The coefficient of static friction is

#F_r=(10.8)/(18g)=0.061#