# An object with a mass of 18 kg is on a surface with a kinetic friction coefficient of  2 . How much force is necessary to accelerate the object horizontally at  17 m/s^2?

Oct 22, 2016

Given
$m \to \text{Mass of the object} = 18 k g$

$a \to \text{Accelerationof the object} = 17 \frac{m}{s} ^ 2$

${\mu}_{k} \to \text{Coefficient of kinetic friction} = 2$

Let the force necessary to maintain the required acceleration be F

$F = m \times a + {\mu}_{k} \times m \times g$

$\implies F = 18 \times 17 + 2 \times 18 \times 9.8 = 658.8 N$