Question

An object with a mass of `2 kg` is on a surface with a kinetic friction coefficient of `7`. How much force is necessary to accelerate the object horizontally at `28 m/s^2`?

Answer 1

`F=193,34 N`

Explanation:

`F_"net"=m*a" "F_"net"=2*28=56 " "N`

`F_f=k.N " "N=m*g" Normal Force"`
`F_f=7*2*9,81" "F_f=137,34 N`
`F_"net"=F-F_f" "F_f":Friction Force"`
`56=F-137,34`
`F=56+137,34`
`F=193,34 N`