An object with a mass of #2 kg# is on a surface with a kinetic friction coefficient of # 7 #. How much force is necessary to accelerate the object horizontally at #6 m/s^2#?

1 Answer
Dec 20, 2015

Answer:

I found: #F=149.2N#

Explanation:

Kinetic Friction is given as:
#f_k=mu_k*N#
Where:
#mu_k=#kinetic friction coefficient#=7#
#N=#Normal Reaction (in this case of horizontal movement)#="weight"=mg#
with:
#m=2kg#
#g=9.8m/s^2#

To produce an acceleration #a=6m/s^2# we need a force #F# to overcome friction that, according to Newton's Second Law, will be given as:
#F-f_k=ma#
#F=f_k+ma#
#F=mu_k*mg+ma#
#F=(7*2*9.8)+(2*6)=149.2N#