An object with a mass of #2 kg# is revolving around a point at a distance of #4 m#. If the object is making revolutions at a frequency of #3 Hz#, what is the centripetal force acting on the object?

1 Answer
Oct 24, 2016

Answer:

I found: #2842N#

Explanation:

Centripetal force is given as:
#F_c=mv^2/r#..............................(1)

We can evaluate the velocity knowing that the object moves of a (linear) distance equal to:
#d=2pir#
and that the frequency (representing the number of turns in one second) is #3Hz# meaning that in one second it will go through #3# complete turns:

So the total liner distance will be:

#d=3*2pir=3*2pi*4=75.4m# in one second corresponding to a velocity (linear):

#v=d/t=75.4/1=75.4m/s#

Using this information into the expression for centripetal force (1) we get:

#F_c=2*(75.4)^2/4=2842N#