# An object with a mass of 2 kg is revolving around a point at a distance of 5 m. If the object is revolving at a rate of 3 Hz, what is the centripetal force on the object?

Jul 29, 2017

${F}_{c} = 3.6 N$

#### Explanation:

The formula for centripetal force is,
${F}_{c} = m {v}^{2} / r$

$m = 2 {k}_{g}$
$v = 3 m {s}^{-} 1$, because $1 {H}_{z} = 1 \sec$
$r = 5 m$

$= 2 {3}^{2} / 5$

$= 3.6 N$