An object with a mass of #2 kg# is revolving around a point at a distance of #5 m#. If the object is revolving at a rate of #5 Hz#, what is the centripetal force on the object?

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Answer 1 · 2017-05-05T12:52:43

I got #9860N#

The rate of #5Hz# means that the object makes #5# revolutions in one second.

This means that it will travel a total linear distance of #d=5*2pir# (five times the circumference) during one second, or:

#d=10*pi*5=157m#

so, also its velocity will be: #d/t=157/1=157m/s#

Now we can use the general expression for a Centripetal Force:

#F_c=ma_c=mv^2/r#

#F=2*(157^2)/5=9859.6~~9860N#