# An object with a mass of 2 kg is revolving around a point at a distance of 5 m. If the object is making revolutions at a frequency of 2 Hz, what is the centripetal force acting on the object?

Jul 3, 2018

The centripetal force is $= 1579.1 N$

#### Explanation:

The centripetal force is

${F}_{C} = m {v}^{2} / r = m r {\omega}^{2}$

The mass of the object is $m = 2 k g$

The radius is $r = 5 m$

The frequency of the rotation is $f = 2 H z$

The angular velocity is

$\omega = 2 \pi f = 2 \pi \cdot 2 = 4 \pi r a {\mathrm{ds}}^{-} 1$

Therefore, the centripetal force is

${F}_{C} = m r {\omega}^{2} = 2 \cdot 5 \cdot {\left(4 \pi\right)}^{2}$

$= 1579.1 N$