An object with a mass of #2# # kg# is revolving around a point at a distance of #7# #m#. If the object is making revolutions at a frequency of #13# # Hz#, what is the centripetal force acting on the object?

1 Answer
Jun 17, 2017

Answer:

#F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405# #N#

Explanation:

The centripetal force is given by:

#F=mr\omega^2#

where #r# is the radius, #m# is the mass and #\omega# is the rotational frequency in #rads^-1#.

To convert a frequency in #Hz# to #rads^-1# we multiply by #2\pi#.

Therefore #F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405# #N#