Question

An object with a mass of `2` `kg` is revolving around a point at a distance of `7` `m`. If the object is making revolutions at a frequency of `13` `Hz`, what is the centripetal force acting on the object?

Answer 1

`F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405` `N`

Explanation:

The centripetal force is given by:

`F=mr\omega^2`

where `r` is the radius, `m` is the mass and `\omega` is the rotational frequency in `rads^-1`.

To convert a frequency in `Hz` to `rads^-1` we multiply by `2\pi`.

Therefore `F =mr\omega^2 =2xx7xx(13xx2\pi)^2 =93 405` `N`