# An object with a mass of 2  kg is revolving around a point at a distance of 7 m. If the object is making revolutions at a frequency of 13  Hz, what is the centripetal force acting on the object?

Jun 17, 2017

$F = m r \setminus {\omega}^{2} = 2 \times 7 \times {\left(13 \times 2 \setminus \pi\right)}^{2} = 93 405$ $N$

#### Explanation:

The centripetal force is given by:

$F = m r \setminus {\omega}^{2}$

where $r$ is the radius, $m$ is the mass and $\setminus \omega$ is the rotational frequency in $r a {\mathrm{ds}}^{-} 1$.

To convert a frequency in $H z$ to $r a {\mathrm{ds}}^{-} 1$ we multiply by $2 \setminus \pi$.

Therefore $F = m r \setminus {\omega}^{2} = 2 \times 7 \times {\left(13 \times 2 \setminus \pi\right)}^{2} = 93 405$ $N$