# An object with a mass of 2 kg is revolving around a point at a distance of 7 m. If the object is making revolutions at a frequency of 1 Hz, what is the centripetal force acting on the object?

Jul 19, 2017

The centripetal force is $= 552.7 N$

#### Explanation:

The centripetal force is

$F = m {v}^{2} / r = m r {\omega}^{2}$

The mass is $= 2 k g$

The radius is $r = 7 m$

The angular velocity is $\omega = 2 \pi f = 2 \pi \cdot 1 = 2 \pi r a {\mathrm{ds}}^{-} 1$

The centripetal force is

$= 2 \cdot 7 \cdot {\left(2 \pi\right)}^{2} = 552.7 N$

Jul 19, 2017

${F}_{c} = 56 {\pi}^{2} N$

#### Explanation:

We will first find the angular velocity :

ω=2pif=2pi*1=2pi(rads)/s

The centripetal force is :

F_c=mω^2r=2*4pi^2*7=56pi^2N