An object with a mass of $25 k g$ $25 kg$ is lying still on a surface and is compressing a horizontal spring by $\frac{5}{2} m$ $5/2 m$ . If the spring's constant is $4 \frac{k g}{s^{2}}$ $4 (kg)/s^2$ , what is the minimum value of the surface's coefficient of static friction?

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Answer 1 · 2016-01-21T00:22:43

I found $0.04$ $0.04$

Have a look:
enter image source here

Answer 2 · 2016-01-21T00:53:47

$μ = \frac{k x}{m g}$ $mu = (kx)/(mg)$
$μ = \frac{2}{49}$ $mu = 2/49$
$μ \approx .04$ $mu ~~ .04$

enter image source here

Take a look at the figure ignore d(t) we will not need it
Now put free body diagram we will have the following equations

An object with a mass of 25kg 25 kg is lying still on a surface and is compressing a horizontal spring by 52m5/2 m. If the spring's constant is 4kgs2 4 (kg)/s^2, what is the minimum value of the surface's coefficient of static friction?