An object with a mass of # 4 kg# is lying on a surface and is compressing a horizontal spring by #8 cm#. If the spring's constant is # 2 (kg)/s^2#, what is the minimum value of the surface's coefficient of static friction?

1 Answer
Feb 2, 2016

Answer:

#mu = 2xx.08/(4xx9.81) = .04/9.81 ~~.004#

Explanation:

Take FBD:
1) y-direction #N = mg #
2) x-direction #F_(ms) = muN#
Insert 1) into 2)
#kx = mumg #
# mu = (kx)/(mg)#
# mu = 2xx.08/(4xx9.81) = .04/9.81 ~~.004#

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