An object with a mass of #4 kg# is on a ramp at an incline of #pi/8 #. If the object is being pushed up the ramp with a force of # 2 N#, what is the minimum coefficient of static friction needed for the object to remain put?

1 Answer
Feb 3, 2018

Answer:

#0.36#

Explanation:

Component of weight of the object acting downward along the inclined plane is #mg sin theta=4*10*sin (pi/8)=15.30 N#

So,unbalanced force acting downwards along the inclined plane is #(15.30-2)N = 13.30N#

So,this amount of force must be supplied by the frictional force upwards.

So,frictional force acting here is #mu*N=mu*mg cos (pi/8)# (#mu# is the desired coefficient of friction)

So, #mu mg cos (pi/8) = 13.50#

or, #mu=0.36#