An object with a mass of $4 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= 5+tanx$ . How much work would it take to move the object over $x in [(-5pi)/12, (pi)/4]$ , where x is in meters?

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An object with a mass of $4 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= 5+tanx$ . How much work would it take to move the object over $x in [(-5pi)/12, (pi)/4]$ , where x is in meters?

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Answer 1 · 2017-05-06T21:13:47

As we know that work $= int_(x_1)^(x_2) vecF.vec (dx)$
Here $F=4xx10xx (5+tanx)=40xx(5+tanx)$
$:.W=int_-((5pi)/12)^(pi/4)40(5+ tanx)dx$
$=200xx(pi/4-(-(5pi)/12))+40[lnsec (pi/4)-lnsec (-(5pi)/12)]$
Now simplify it...

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An object with a mass of $4 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= 5+tanx$ . How much work would it take to move the object over $x in [(-5pi)/12, (pi)/4]$ , where x is in meters?

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An object with a mass of 4 kg4 kg is pushed along a linear path with a kinetic friction coefficient of u_k(x)= 5+tanx u_k(x)= 5+tanx . How much work would it take to move the object over x in [(-5pi)/12, (pi)/4]x in [(-5pi)/12, (pi)/4], where x is in meters?

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An object with a mass of $4 kg$ is pushed along a linear path with a kinetic friction coefficient of $u_k(x)= 5+tanx$ . How much work would it take to move the object over $x in [(-5pi)/12, (pi)/4]$ , where x is in meters?