An object with a mass of #5 kg# is on a surface with a kinetic friction coefficient of # 2 #. How much force is necessary to accelerate the object horizontally at #12 m/s^2#?

1 Answer
Mar 29, 2016

Answer:

#=(60+98)=158N#

Explanation:

Net force on the body = its mass(m)#xx#acceleration (a)
#5kgxx12ms^-2=60N#
Horce of friction = coefficient of friction#(mu)xx# Nomalreaction #mg#
#=2xx5xx9.8=98N#
So necessary force to be applied #=(60+98)=158N#