An object with a mass of #5 kg# is on a surface with a kinetic friction coefficient of # 2 #. How much force is necessary to accelerate the object horizontally at #6 m/s^2#?

1 Answer
Sunayan S
Jul 6, 2017

#130N#

Explanation:

To equalize the frictional force, we have to give force #mumg=2×5×10=100N#
Next,we have to give force #5×6=30N# force for acceleration.
Hence total force is #100+30=130N#

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