An object with a mass of #5 kg# is on a surface with a kinetic friction coefficient of # 3 #. How much force is necessary to accelerate the object horizontally at #2 m/s^2#?

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Answer 1 · 2017-02-11T12:05:10

#157N#

law of friction#" "F=muxxR#

#R=5g" where "g=9.8ms^(-2)#

we will leave the calculation of #g# until the end.

so #F=3xx5g=15g ""N#

N2L

#F_(res)=ma#

Let #P=#the force required

#P-15g=5xx2#

#P=10+15g=10+147=157N#