# An object with a mass of 5 kg is on a surface with a kinetic friction coefficient of  3 . How much force is necessary to accelerate the object horizontally at 2 m/s^2?

Feb 11, 2017

$157 N$

#### Explanation:

law of friction$\text{ } F = \mu \times R$

$R = 5 g \text{ where } g = 9.8 m {s}^{- 2}$

we will leave the calculation of $g$ until the end.

so F=3xx5g=15g ""N

N2L

${F}_{r e s} = m a$

Let $P =$the force required

$P - 15 g = 5 \times 2$

$P = 10 + 15 g = 10 + 147 = 157 N$